Question

If alpha and beta are roots of quadratic equation 2x^2 – 3x + 1 = 0, then find the equation whose roots are 2alpha/beta and 2beta/alpha

Answer 1

for a new equation,

given zeroes,

are,

$\frac{2 \alpha }{ \beta } \: \: \: \: \: \: \: \: and \: \: \: \: \frac{2 \beta }{ \alpha} \\ \\ \\ according \: to \: quadratic \: equation \: formula \:$

Answer 2

Step-by-step explanation:

for a new equation,

given zeroes,

are,

\begin{lgathered}\frac{2 \alpha }{ \beta } \: \: \: \: \: \: \: \: and \: \: \: \: \frac{2 \beta }{ \alpha} \\ \\ \\ according \: to \: quadratic \: equation \: formula \:\end{lgathered}

β

2α

and

α

2β

accordingtoquadraticequationformula