if alpha and beta are the two zeroes of the polynomial 25p²-15p+2, find a quadratic polynomial whose zeroes are 1/2alpha and 1/2beta.
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Answered by
62
Hello,
P(X) => 25P²-15P+2
Here,
A = 25 , B = -15 and C = 2
Sum of zeroes = -B/A
Alpah + Beta = -(-15)/25
Alpha + Beta = 15/25
And,
Product of zeroes = C/A
Alpha × Beta = 2/25
Sum of Zeroes of Quadratic polynomial whose zeroes are 1/2 ×Alpha and 1/2Beta
Sum of zeroes = 1/2Alpha + 1/2Beta
=> 1/2 × (Alpha + Beta)/(Alpha × Beta)
=> 1/2 × (15/25)/(2/25) = 1/2 × 15/2 = 15/4
And,
Product of zeroes = 1/ 2 Alpha × 1/2 beta = 1/4 Alpna × Beta = 1/ 4 × 2/25
=> 25/8
Therefore,
Required Quadratic polynomial = X²-(Alpha + Beta)X + Alpha × Beta
=> X² - 15/4 X + 25/8
=> X²-15X/4 + 25/8
=> 8X²-30P+25
HOPE IT WILL HELP YOU....... :-)
P(X) => 25P²-15P+2
Here,
A = 25 , B = -15 and C = 2
Sum of zeroes = -B/A
Alpah + Beta = -(-15)/25
Alpha + Beta = 15/25
And,
Product of zeroes = C/A
Alpha × Beta = 2/25
Sum of Zeroes of Quadratic polynomial whose zeroes are 1/2 ×Alpha and 1/2Beta
Sum of zeroes = 1/2Alpha + 1/2Beta
=> 1/2 × (Alpha + Beta)/(Alpha × Beta)
=> 1/2 × (15/25)/(2/25) = 1/2 × 15/2 = 15/4
And,
Product of zeroes = 1/ 2 Alpha × 1/2 beta = 1/4 Alpna × Beta = 1/ 4 × 2/25
=> 25/8
Therefore,
Required Quadratic polynomial = X²-(Alpha + Beta)X + Alpha × Beta
=> X² - 15/4 X + 25/8
=> X²-15X/4 + 25/8
=> 8X²-30P+25
HOPE IT WILL HELP YOU....... :-)
Answered by
44
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