if alpha and beta are the zeroes of the polynomial 2xsquare-7x+3 , then find the sum of the reciprocal of the zeroes
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Step-by-step explanation:
assuming alpha = m and beta = n as they will be easier to write
The given quadratic polynomial :-
→ 2ײ — 7x + 3, here a = 2, b = -7, and c = 3
We have to find :-
→ 1/m + 1/n
→ (m + n)/mn
→ (-b/a)/(c/a)
→ -b/c
→ -(-7)/3
→ 7/3
→ 2.3333......
Hope this helps.....
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