Math, asked by maxkiller, 1 year ago

if alpha and beta are the zeroes of the polynomial f (x)= x^2 -5x +k such that alpha-beta=1, find the value of k.

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Answered by nitthesh7
23
☺☺☺ Hope this Helps ☺☺☺

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nitthesh7: hey bro... if u have any more doubts ask in question column and send me the link in my "profile comments", So that I can help u at most ☺☺☺
maxkiller: thank u mahn ✌✌
maxkiller: i am going to write my last board exam on 28th
nitthesh7: same here bro.. all the best for ur maths xam
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Answered by Anonymous
3

Gɪᴠᴇɴ :

α & β are zeroes of polynomial f(x).

Where,

f(x) = x² - x - k

Wᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,

➣ The general form of an quadratic polynomial is,

\red\bigstar\:\:{\underline{\orange{\boxed{\bf{\green{x^2\:-\:(\alpha\:+\:\beta)\:x\:+\:\alpha\:\beta}}}}}} \\

➣ Compare given quadratic polynomial to the general form of quadratic equation, we get

➾ α + β = 1 ----(a)

Aɴᴅ,

➾ αβ = -k ----(i)

Aᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ᴛʜᴇ ǫᴜᴇsᴛɪᴏɴ,

➾ α - β = 9 ----(b)

➣ Now adding equation (a) & (b), we get

⇒ α + β + α - β = 1 + 9

⇒ 2α = 10

⇒ α = \rm{\dfrac{10}{2}}

\bf\orange{\alpha\:=\:5} \\

➣ Putting the value of α in equation (a), we get

➾ α + β = 1

➾ 5 + β = 1

➾ β = 1 - 5

\bf\blue{\beta\:=\:-4} \\

➣ Let us putting the value of α & β in equation (i), we get

:\implies 5 × (-4) = -k

:\implies -20 = -k

:\implies {\underline{\red{\boxed{\bf{\pink{k\:=\:20}}}}}}\:\green\bigstar \\

\Large\bf\purple{Therefore,}

The value of 'k' is 20.

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