If alpha and beta are the zeroes of the polynomial x^2-3x+k , such that alpha-beta=1, find the value of k
Answers
Question:
If α and ß are the zeros of the given polynomial
x² - 3x + k , such that α - ß = 1 , then find the value of k .
Answer:
k = 2
Note:
• A polynomial of degree 2 is called quadratic polynomial.
• The general form of a quadratic polynomial is given by ; ax² + bx + c = 0 .
• The possible values of variable ( or unknown ) for which the polynomial becomes zero are known as its zeros.
• If α and ß are the zeros of the quadratic polynomial ax² + bx + c , then ;
Sum of zeros , (α + ß) = -b/a
Product of zeros , α•ß = c/a
• If α and ß are the zeros of any quadratic polynomial then that polynomial is given as ;
x² - (α + ß)x + α•ß .
Solution:
Here ,
The given quadratic polynomial is ; x² - 3x + k
Clearly , we have ;
a = 1
b = -3
c = k
Now,
The sum of the zeros of the given quadratic polynomial is ;
=> α + ß = -b/a
=> α + ß = -(-3)/1
=> α + ß = 3 ------(1)
Also,
The product of zeros of the given quadratic polynomial is ;
=> α•ß = c/a
=> α•ß = k/1
=> α•ß = k -------(2)
Also,
It is given that ,
α - ß = 1 ------(3)
Now,
We know that ; (x + y)² - (x - y)² = 4xy
Thus,
=> (α + ß)² - (α - ß)² = 4αß
=> 3² - 1² = 4k
=> 4k = 3² - 1²
=> 4k = 9 - 1
=> 4k = 8
=> k = 8/4
=> k = 2
Hence,
The required value of k is 2 .
Answer:-
Given polynomial => x² - 3x + k = 0
We know that,
Add both the equations,
Substitute , the roots in the given polynomial.
(2)² - 3(2) + k = 0
4 - 6 + k = 0
k = 2
(Or)
(1)² - 3(1) + k = 0
1 - 3 + k = 0
k = 2
Hence, the value of k is 2.