Question

if alpha and beta are the zeros of f(x)= x2-c(x+1)-c, then (alpha+1)(beta+1)=?

Answer 1

hope this helped you.........

Answer 2

heya...........


Given that alpha and beta are the roots of the quadratic equation  f(x) = x^2-c(x+1)-c = x^2-cx-c-c = x^2 -cx-(c+c),

comparing with ax^2 + bx + c, we have, a =1 , b= -c & c= -(c+c)

alpha+beta = -b/a = -(-c)/1 = c

& alpha*beta = c/a = -(c+c)/1 = -(c+c)

Therefore, (Alpha + 1)*(beta+1) 

= Alpha*beta + alpha + beta + 1 

= -(c+c) + c + 1

= -c-c+c+1

= 1-c




tysm.........#gozmit