if alpha and beta are the zeros of quadratic polynomial FX = to 6 X square + X - 2 then find the value of Alpha square plus beta square
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Answered by
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see the attachment above...
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i hope this will help
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i hope this will help
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Answered by
14
HELLO DEAR,
6X² + X - 2 = 0
where,
a = 6
b = 1
c = (-2)
now,
we know that:-
α * β = c/a
α + β = -b/a = 1/6
now on squaring both side,
we get,
α² + β² + 2αβ = 1/36
α² + β² = 1/36 - 2(-2/6)
α² + β² = 1/36 + 2/3
α² + β² = (3 + 72)/108
α² + β² = 75/108
α² + β² = 25/36
I HOPE ITS HELP YOU DEAR,
THANKS
6X² + X - 2 = 0
where,
a = 6
b = 1
c = (-2)
now,
we know that:-
α * β = c/a
α + β = -b/a = 1/6
now on squaring both side,
we get,
α² + β² + 2αβ = 1/36
α² + β² = 1/36 - 2(-2/6)
α² + β² = 1/36 + 2/3
α² + β² = (3 + 72)/108
α² + β² = 75/108
α² + β² = 25/36
I HOPE ITS HELP YOU DEAR,
THANKS
ShivamSingh111111:
ans is wrong
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