Math, asked by RajatGupta2708, 1 month ago

if alpha and beta are the zeros of the polynomial p(y)= 5y^2-7y+1 find alpha^2-beta^2​

Answers

Answered by MissWhiteHoney
3

Given f(x) = 5y^2 - 7y + 1.

Given that a,b be the zeros of the polynomial.

We know that sum of zeroes = -b/a

= > a + b = -(-7/5)

= > a + b = 7/5.

We know that product of zeroes = c/a

= > ab = 1/5

Now,

= > 1/a + 1/b = (a + b)/ab

                    = (7/5) * (5/1)

                    = 7/1

                    = 7.

Hope this helps!

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Answered by itzbhavesh282
2

Answer:

Since are the zeroes of the polynomials

p(y) = 5y2 – 7y + 1

Sum of the zeroes

-coeeficient of x

coefficient of

α+β=-coeeficient of xcoefficient of x2

=--75

=75

Product of zeroes

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