if alpha and beta are the zeros of the polynomial p(y)= 5y^2-7y+1 find alpha^2-beta^2
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Answered by
3
Given f(x) = 5y^2 - 7y + 1.
Given that a,b be the zeros of the polynomial.
We know that sum of zeroes = -b/a
= > a + b = -(-7/5)
= > a + b = 7/5.
We know that product of zeroes = c/a
= > ab = 1/5
Now,
= > 1/a + 1/b = (a + b)/ab
= (7/5) * (5/1)
= 7/1
= 7.
Hope this helps!
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Answered by
2
Answer:
Since are the zeroes of the polynomials
p(y) = 5y2 – 7y + 1
Sum of the zeroes
-coeeficient of x
coefficient of
α+β=-coeeficient of xcoefficient of x2
=--75
=75
Product of zeroes
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