If alpha and beta are zeroes of qudratic polynomial f(x) = x²+x-6 then polynomial whose zeroes are 2 alpha + 1 and 2 beta + 1 ...
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LET ALPHA = A AND BETA = B
A + B = -1
AB = -6
SUM OF ROOTS =
2A+1+2B+1
= 2A+2B+2
= 2(A+B)+2
= 2(-1)+2
-2+2
= 0
PRODUCT OF ROOTS =
(2A+1)(2B+1) = 4AB +2A+2B+1
= 4AB +2(A+B) +1
= 4(-6)+2(-1)+1
= -24-2+1
= -25
POLYNOMIAL WITH 2A+1 AND 2B+1 AS ZEROS
IS X² - X ( 2A+1+2B+1) + (2A+1)(2B+1)
X²-X(SUM OF ROOTS) + PRODUCT OF ROOTS
X²- X(0) + (-25)
X²-25
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