Question

if alpha and beta are zeros of a polynomial p(x)=x²+x+1 , then find the value of 1/alpha and 1/ß and
alpha²+beta²

Answer 1

$\frac{1}{ \alpha } + \frac{1}{ \beta } = \alpha + \beta \div \alpha \beta \\ from \: the \: equation \: w e \: get \: \alpha + \beta = - b \div a = - 1 \\ nd \\ \\ and \: \alpha \beta = c \div a = 1 \\ \\ than \: \frac{ \alpha + \beta }{ \alpha \beta } = \frac{( - 1}{1} = - 1$
and alpha ^2 +beta ^2=(alpha+beta)^2 -2 alpha×beta

=-1^2 -2×1.

=1-2
-1





hope it's helpful to you....