Question

if alpha beta are the the zeroes of 9x^2 + 5x-1 find the value of alpha square and beta square​

Answer 1

Step-by-step explanation:

D =

${5}^{2} + 36 \\ = 61 \\ \\ \alpha = \frac{ - 5 + \sqrt{61} }{18} \\ \\ \beta = \frac{ - 5 - \sqrt{61} }{18}$

Answer 2

Step-by-step explanation:

$\alpha = - b \div a \\ = - 5 \div 9 \\ \beta = c \div a \\ \\ \ \ - 1 \div 9$

$\alpha { }^{2} = - 5 \div 9 {}^{2} \\ = 25 \div 81 \\ \beta {}^{2} = - 1 \div 9 {}^{2} \\ = 1 \div 81$