Math, asked by dnm, 1 year ago

if alpha ,beta ,gamma are the zeros of the polynomial 2x^3 + x^2 - 13x + 6 then alpha•beta• gamma=.......

Answers

Answered by mysticd
49

Answer:

\alpha \cdot \beta \cdot \gamma \\=  \green {-3}

Step-by-step explanation:

 \alpha ,\:\beta \:and \: \gamma \:are \: the \\zeros \:of \: the \: polynomial \\2x^{3}+x^{2}-13x+6

/* Compare above polynomial by ax³+bx²+cx+d ,we get

 a = 2 , b = 1 , c = -13 , d = 6

\alpha \cdot \beta \cdot \gamma \\= \frac{-d}{a}\\= \frac{-6}{2} \\= \green {-3}

Therefore.,

\alpha \cdot \beta \cdot \gamma \\=  \green {-3}

•••♪

Answered by ankitbhardwaj08285
8

Answer:

-3 is the right answer. Thank you

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