Question

If alpha, beta, ghama are the zeroes of the polynomials f (x) = X cube--px square +qx, then find 1/alpha bheta,+ 1/bheta ghama +alpha ghama​

Answer 1

Answer

F(x)=x³+px²+qx.

Let alpha be a, beta be b, gamabe g

Therefore,

ab+bg+ga=c/a-co..eff of x/co..eff of x³

1/ab+bg+ga=a/c

=1/q