Question

if an ap sn=n(4n-1), find the Ap​

Answer 1

Answer:

if n=1

S1=1(4*1-1)

=3

if n=2

S2=2(8-1)

=14

S2-S1=14-3=11

so the Ap series is Ap=3,11,19,27.....

Answer 2

Answer:

Heya........

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Here's ur answer :

»» Sn = n(4n-1) = 4n² - n

Substituting n = 1, we get

S1 = 4(1)² - 1 = 4 - 1 = 3

Thus, first term , a1 = 3

Substituting n = 2 , we get

S2 = 4(2)² - 2 = 16 - 2 = 14

& a2 = S2 - S1 = 14 - 3 = 11

Substituting n = 3 , we get

S3 = 4(3)² - 3 = 36 - 3 = 33

& a3 = S3 - S2 = 33 - 14 = 19

Thus, the first term is a1 = 3 and the common difference = 19 - 11 = 11 - 3 = 8

Hence, Required A.P. = 3,11,19,27,......

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✨ Hope it helps ✨