if an area of an isosceles right angled triangle is 32 cm square. find the sides of the triangle
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The area of isosceles right angled triangle = 32
x²/2 = 32
x² = 32×2 = 64
x = 8
√2(8²) = √128
= 8√2
so, sides are 8,8,8√2
Hope it helps u :-)
x²/2 = 32
x² = 32×2 = 64
x = 8
√2(8²) = √128
= 8√2
so, sides are 8,8,8√2
Hope it helps u :-)
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