Question

If an object of mass 10kg is performing linear motion with acceleration of 4m/s^2,find out change occurring in its momentum in 5 seconds.​

Answer 1

Answer:

Change in the momentum of the object is 200 Ns

Explanation:

As we know that the mass of 10 kg is moving here with given acceleration

$a = 4 m/s^2$

now we can use Newton's II law to find the net force on it

$F_{net} = ma$

$F_{net} = 10(4)$

$F_{net} = 40 N$

now we know that

$F_{net} = \frac{\Delta P}{\Delta t}$

so we can find the change in momentum as

$\Delta P = F_{net} \Delta t$

$\Delta P = 40(5)$

$\Delta P = 200 Ns$

#Learn

Topic : Newton's 2nd law

https://brainly.in/question/5101848

Answer 2

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Given :

• Mass of Object (m) = 10 kg
• Acceleration of Object (a) = 4/s²
• Time (t) = 5 s

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To Find :

• Change in Momentum

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Solution :

We have formula for ΔP or say for change in momentum :

$\large{\boxed{\sf{F \: = \: \dfrac{\Delta P}{\Delta t}}}} \\ \\ \implies {\sf{\Delta P \: = \: F \Delta t}} \\ \\ \implies {\sf{\Delta P \: = \: ma \: \times \: \Delta t}} \\ \\ \implies {\sf{\Delta P \: = \: 10 \: \times \: 4 \: \times \: 5}} \\ \\ \implies {\sf{\Delta P \: = \: 50 \: \times \: 4}} \\ \\ \implies {\sf{\Delta P \: = \: 200}} \\ \\ \underline{\sf{\therefore \: Change \: in \: momentum \: is \: 200 \: Ns}}$