Question

If α and β are the zeroes of the equation 6x²+x-2=0, find (α÷β) + (β÷α) .
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Answer 1

The answer is right Below in the attachment. Hope it helps :)

Answer 2

a+ß = -1/6
aß = -2/6 = -1/3

Now, a/ß + ß/a = (a2 + ß2) / (a+ß)
= [(a+ß)^2 - 2aß] / (a+ß)
= [(-1/6)^2 - (2*-1/3)] / (-1/3)
= (1/36 + 2/3) / -1/3
= 25/36 ÷ -1/3
= (25*-3) / 36
= -25/12

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