Question

If α and β are the zeroes of the polynomial 2x^2 - 7x + 3 find α^3 + β^3​

Answer 1

splitting the middle term ...
then u get the zeros
then put alpha cube and bita cube formula ..solve it
got the required answer

Answer 2

Step-by-step explanation:

2x^2 - 7x + 3

sum of zeros = α+β = 7/2

product of zeros = αβ = 3/2

α^3 + β^3 = (α+β)(α^2+β^2-αβ)

=(7/2)(α^2+β^2+2αβ-2αβ-αβ)

=(7/2)[(α+β)^2-3αβ]

=(7/2)(49/4-9/2)

=(7/2)(31/4)

=217/8