if angles of a quadrilateral are 2 X + 10 degrees X + 20 degrees X + 30 degrees and x minus 10 degrees then find x
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madhu131:
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5X +50 = 360°
5X = 310
hence X = 62
Then angles are....
2X +10 = 134
X + 20 = 82
X + 30 = 92
X - 10 = 52...answer
5X = 310
hence X = 62
Then angles are....
2X +10 = 134
X + 20 = 82
X + 30 = 92
X - 10 = 52...answer
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