Question

if any body is genius so solve this problem from 7th class
(2/3)^3 * (2/3)^6 = (4/9)^2k-3
find the value of k i this mathematical problem

Answer 1

Let t = 2/3(FOR CONVENIENCE).

Thus t² = 4/9.

If we compare the exponents of t,

we know that $2(2k-3)=9$.

$4k-6=9$

∴$x=\frac{15}{4}$