If α,β are the roots of ax²+bx+c=0 and the roots of the polynomial px²+qx+r=0 are 1-α/α and 1-β/β.find the value of r.I want u to explain it.
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r is the multiplication of the 2 roots then
r = (1-B)×(1-@)/@B
r = [1+@B-(@+B)]/@B
but from the first equation we have @B = c/a
and @+B = -b/a
then, r = [1 + c/a + b/a]/(c/a)
by solving the equation we get r is (a+b+c)/c
r = (1-B)×(1-@)/@B
r = [1+@B-(@+B)]/@B
but from the first equation we have @B = c/a
and @+B = -b/a
then, r = [1 + c/a + b/a]/(c/a)
by solving the equation we get r is (a+b+c)/c
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