Question

If α,βα,β  are the roots of the quadratic equation x2+2x+1=0x2+2x+1=0  then the quadratic equation with the roots 4α,4β4α,4β  is​

Answer 1

Step-by-step explanation:

sum of roots of ax^2+bx+c is-b/a and

product of roots is c/a

for x²+2x+1

sum of roots = -2/1 =-2, product of roots = 1/1 =1

a+b = -2, ab = 1

4a+4b = 4×(a+b) = 4×(-2) = -8

4a×4b =16ab =16×1 =16

x²-(sum of roots)x+product of roots =0

x²-(-8)x+16 = 0

x²+8x+16 =0

Answer 2

Step-by-step explanation:

0 is the correct answer .

hope it helps you.