Question

. If area of quadrant of a circle is 38.5 cm2 then find its diameter (use π = 22/7 )​

Answer 1

Apply the formula for area of quadrant:

$\rm\frac{\theta}{360} × \pi R^2$ = 38.5

$\rm\frac{90}{360} × \pi R^2$ = 38.5

$\rm\frac{1}{4} × \pi R^2$ = 38.5

$\pi R^2 = 38.5 × 4$

$\frac{22}{7} R^2 = 154$

$R^2 = \frac{154 × 7}{22}$

R² = 49

R = √49

R = 7 cm

So, Diameter = 2R = 2×7cm = 14cm

Answer 2

Answer:

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