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Akanksha07:
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Because N=n(n+1)(n−1) is a product of three consecutive numbers it is a multiple of both 2 and 3 so a multiple of 6. Besides N=2n+1 gives
N=(2n+1)(2n+2)(2n=4(2n+1)(n+1)n
and N is also a multiple of 4 so N=24t for some integer t.(Note that (n+1)n is even)
N=(2n+1)(2n+2)(2n=4(2n+1)(n+1)n
and N is also a multiple of 4 so N=24t for some integer t.(Note that (n+1)n is even)
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