Question

If arrays M and M + N are shown below, write a program in Java to find the array N.
[tex] \text{M} \: = \left[
\ \textless \ br /\ \textgreater \ \begin{array}{c c c}
\ \textless \ br /\ \textgreater \ - 1 & 0 & 2 \\
\ \textless \ br /\ \textgreater \ - 3 & - 1 & 6 \\
\ \textless \ br /\ \textgreater \ 4 & 3 & - 1
\ \textless \ br /\ \textgreater \ \end{array}
\ \textless \ br /\ \textgreater \ \right][/tex]
[tex] \text{and \: M+N} = \left[
\ \textless \ br /\ \textgreater \ \begin{array}{c c c}
\ \textless \ br /\ \textgreater \ - 6 & 9 & 4 \\
\ \textless \ br /\ \textgreater \ 4 & 5 & 0 \\
\ \textless \ br /\ \textgreater \ - 1 & - 2 & - 3
\ \textless \ br /\ \textgreater \ \end{array}
\ \textless \ br /\ \textgreater \ \right][/tex]








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Answer 1

$\texttt{\textsf{\large{\underline{Solution}:}}}$

Here comes the approach for the problem.

public class FindMatrix{

   public static void main(){

       int matrix_M[][]={{-1,0,2},{-3,-1,6},{4,3,-1}};

       int matrix_M_N[][]={{-6,9,4},{4,5,0},{1,-2,-3}};

       int matrix_N[][]=new int[3][3];

       System.out.println("Matrix M:");

       displayMatrix(matrix_M);

       System.out.println("\nMatrix M+N: ");

       displayMatrix(matrix_M_N);

       for(int i=0;i<3;i++){

           for(int j=0;j<3;j++)

               matrix_N[i][j]=matrix_M_N[i][j]-matrix_M[i][j];

           }

       System.out.println("\nSo, Matrix N will be: ");

       displayMatrix(matrix_N);

   }

   static void displayMatrix(int a[][]){

       for(int i[]:a){

           for(int j:i)

               System.out.print(j+"  ");

           System.out.println();

       }

   }

}

$\texttt{\textsf{\large{\underline{Logic}:}}}$

• Here, we are provided with the matrices M+N and M. So, to get matrix N, we will subtract matrix M from matrix M+N.

See the attachment for output.

Answer 2

Answer:

public class KboatSubtractDDA

{

public static void main(String args[]) {

int arrM[][] = {

{-1, 0, 2},

{-3, -1, 6},

{4, 3, -1}

};

int arrSum[][] = {

{-6, 9, 4},

{4, 5, 0},

{1, -2, -3}

};

int arrN[][] = new int[3][3];

for (int i = 0; i < 3; i++) {

for (int j = 0; j < 3; j++) {

arrN[i][j] = arrSum[i][j] - arrM[i][j];

}

}

System.out.println("Array N:");

for (int i = 0; i < 3; i++) {

for (int j = 0; j < 3; j++) {

System.out.print(arrN[i][j]);

System.out.print(' ');

}

System.out.println();

}

}

}

hope it's helpful