if avalanch takes 2 second to fall 20 m how far it fall in half second if the time taken by an avalanch to fall is proporation to the square root of the distance it falls
Answers
Ans
S=d/s
S=20/2
S=10
So Avalanche travels in 1 second 10m/s
It travels in 1/2 second 5m/s
So,
D=k(t)square
5= k (2)square
5/4=k
1.25m=k
Avalanche will fall 1.25 m in 1/2 sec if time taken is in proportion to square root of distance covered and it falls 20 m in 2 sec
Step-by-step explanation:
Time taken ∝ √(Distance Covered)
Time taken = K √(Distance Covered)
K = Constant
Time Taken = 2 sec
Distance covered = 20 m
=> 2 = K √20
=> K = 2/√20
Time = 1/2 sec
Distance covered = D
=> 1/2 = K √D
=> 1/2 = (2/√20) √D
=> √D = √20/4
Squaring both sides
=> D = 20/16
=> D = 1.25 m
Distance covered = 1.25 m in 1/2 secs
Avalanche will fall 1.25 m in 1/2 sec if time taken is in proportion to square root of distance covered and it falls 20 m in 2 sec
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