If ax+by=3,bx-ay=4 and x square+y square=1,then the value of a square+b square is
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Answer:
the value of a² + b² = 25
Step-by-step explanation:
squaring both the equations
we have
a²x² + b²y² + 2abxy = 9
b²x² + a²y² - 2abxy = 16
adding both equations
(a² + b²)x² + (a² + b²)y² = 25
given x² + y² = 1
so
(a² + b²) (x² + y²) = 25
thus
a² + b² = 25
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