Question

If ax2

– 9x + 15 is a quadratic polynomial and

product of its zeroes is –6, then find the value of a.​

Answer 1

Answer:

-5/2 or -2.5

Step-by-step explanation:

hey mate

solution:

given:

quadratic expression=ax²-9x+15

product of the roots=-6

to find:

a=?

Method I:

we know that,

product of roots=constant term(c)/coefficient of x²(a)

=>-6=15/a

=>a=-5/2 or -2.5

some additional information:

*quadratic expression:an algebraic expression in which variable involved has a power of highest 2 degree.that is it's degree is 2.

*the standard or general form of equation is ax²+bx+c where a,b,c are real numbers and a≠0.

*quadratic formula or shreedharcharya's rule=

(-b±√(b²-4ac))/2a

*sum of roots= - coefficient of x(b)/coefficient of x²(a)

*product of roots=constant term(c)/coefficient of x²(a)

Answer 2

Given quadratic polynomial is

ax^2 - 9x + 15

Product of its zeroes is given by 15/a

Given, 15/a = - 6

or, a/15 = - 1/6

or, a = - 15/6

or, a = - 5/2

So the value of a is (- 5/2).