Question

if (b-c)2, (c-a)2, (a-b)2 are in ap, show that 1/b-c, 1/c-a, 1/a-b are also in ap. ​

Answer 1

Answer:

if (b-c)^2,(c-a)^2,(a-b)^2 are in AP, prove that 1/(b-c),1/(c-a),1/(a-b) ...