If B lies on line AC and points A, B and C are distinct such that, AB + BC = AC, then
A.
AB < AC
B.
AB > AC
C.
AB = AC
D.
None of these
Anonymous:
answer is D
Answers
Answered by
3
Hey there !!
⨷ Answer ➣ Option A ) AB <AC
Explanation -
Here suppose ABC is the line Given that
In Option
B ) Which states AB> AC , it is not possible because AB + BC = AC , as AC is Greater and AB And BC By sum to make equal with AC
C) AB = AC
It isn't an Desired answer because AB ≠ AC
if it would have then AB + BC = AC
Hence Option A is right one
Hope this would help you !!
⨷ Answer ➣ Option A ) AB <AC
Explanation -
Here suppose ABC is the line Given that
In Option
B ) Which states AB> AC , it is not possible because AB + BC = AC , as AC is Greater and AB And BC By sum to make equal with AC
C) AB = AC
It isn't an Desired answer because AB ≠ AC
if it would have then AB + BC = AC
Hence Option A is right one
Hope this would help you !!
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Answered by
8
HELLO DEAR,
WE SOMETIMES WILL WRITE A-B-C, WHICH MEANS "B IS BETWEEN A AND C."
THE DEFINITION USES DISTANCE
, AND APPLYING THE CONCEPT OF A
COORDINATE SYSTEM WE HAVE THE
FOLLOWING THEOREM.
BY THE RULER POSTULATE:
AB = |y-x|
BC = |z-y|
AC = |z-x|.
BUT y-x IS POSITIVE BECAUSE x < y; SIMILARLY, z-y AND z-x ARE POSITIVE. SO:
AB = y-x
BC = z-y
AC = z-x
FINALLY:
AB + BC = (y - x) + (z - y)
= z-x
=AC.
SINCE AB + BC = AC, A-B-C BY THE DEFINITION OF BETWEEN.
AND HENCE,
AB<AC
I HOPE ITS HELP YOU DEAR,
THANKS
WE SOMETIMES WILL WRITE A-B-C, WHICH MEANS "B IS BETWEEN A AND C."
THE DEFINITION USES DISTANCE
, AND APPLYING THE CONCEPT OF A
COORDINATE SYSTEM WE HAVE THE
FOLLOWING THEOREM.
BY THE RULER POSTULATE:
AB = |y-x|
BC = |z-y|
AC = |z-x|.
BUT y-x IS POSITIVE BECAUSE x < y; SIMILARLY, z-y AND z-x ARE POSITIVE. SO:
AB = y-x
BC = z-y
AC = z-x
FINALLY:
AB + BC = (y - x) + (z - y)
= z-x
=AC.
SINCE AB + BC = AC, A-B-C BY THE DEFINITION OF BETWEEN.
AND HENCE,
AB<AC
I HOPE ITS HELP YOU DEAR,
THANKS
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