Question

If both the zeroes of the quadratic polynomial ax2

+ bx + c are equal and opposite in sign, then find

the value of 'b'?.​

Answer 1

Answer:—

The "value of b" is zero.

To find:

The value of b

Solution:

Let us consider f to be one of the zeroes of the quadratic polynomial ax²+bx+c

Thus,

The other zero of the polynomial, which is equal and opposite in sign will be = -f.

We know,

For a quadratic polynomial represented as ax²+bx+c

Sum of the zeroes = -b/a

$\begin{gathered}\begin{array} { c } { f + ( - f ) = - \frac { b } { a } } \\\\ { - \frac { b } { a } = f - f } \\\\ { - \frac { b } { a } = 0 } \\\\ { - b = 0 \times a = 0 } \\\\ { b = 0 } \end{array}\end{gathered}$

Thus,

The "value of b" for the quadratic polynomial ax²+bx+c is 0.

@vikram