Math, asked by suraj6933, 1 year ago

If c(x)=5/X-2 and d(x) = x + 3, what is the domain of (cd)(x)?
all real values of x
all real values of x except x = 2
all real values of x except x = –3
all real values of x except x = 2 and x = –3

Answers

Answered by shubham0204
13

Answer:

all real values except x = 2

Step-by-step explanation:

(c \times d)(x) = c(x) \times d(x) \\  =  \frac{5}{x - 2}  \times x + 3 \\  =  \frac{5x + 15}{x - 2}

Hence, the function is defined for all values except 2 ( 2 - 2 in the denominator becomes 0 and division by zero is undefined ). Hence,

Domain = R - { 2 } or all real numbers except 2.

Answered by ChiKesselman
7

Option B) all real values of x except x = 2

Step-by-step explanation:

We are given the following in the question:

c(x) = \dfrac{5}{x-2}\\\\d(x) = x + 3

First we will evaluate (cd)(x)

(cd)(x) = \dfrac{5}{x-2}\times (x+3) = \dfrac{5(x+3)}{x-2}

We have to find the domain of the resultant function.

The domain is all the possible values that x can take so that the function is defined.

Thus, the domain of (cd)(x) is

x \in (-\infty,\infty)-\{2\}

That is the domain is all real numbers except x = 2.

Thus, the correct answer is

Option B) all real values of x except x = 2

#LearnMore

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