Question

If cos 7A = sin(A − 6°), where 7A is an acute angle, find the value of A.

Answer 1

Hey mate

Here is ur answer

cos 7A = sin(A − 6°)
Sin (90° - 7A) = Sin (A - 6°)
90° - 7A = A - 6°
90 + 6 = A + 7A
96 = 8A
A = 96/8
A = 12°

Answer 2

Hey there!

Given that, cos7A = sin(A − 6°),



$\textbf{Since, cosØ = sin(90-Ø )}$

$=> cos7A = sin(A -6 ) \\ \\ => sin( 90 - 7A ) = sin ( A - 6 ) \\ \\ => 90 - 7A = A -6 \\\\ => 90 + 6 = A + 7A \\\\ => 96 = 8A => \frac{96}{8} = A => A = 12°$

$\boxed{ \boxed{ \textbf{The measure of Angle A = 12° }}}$

Hope helped!