Question

If cos (90

-A)=0, then Sin (A+B)=​

Answer 1

Answer:

sin(A+B) = sinB

Given cos (90°-A) = 0

We know cos (90°-A) = sin A hence sinA = 0 and cosA = 1

We also know sin (A+B) = sinA.cosB +cosA.sin B

Putting above values We get sin(A+B) = 0.cosB + 1.sinB = sinB

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