Question

If cos A = 0.5 and cos B = 1\√2: find the value of : tan A - tan B \ 1 + tan A tan B

Answer 1

CosA = 0.5
⇒A = 60°
cosB = 1/√2
⇒B = 45°
A/q
(tanA - tanB)/(1 +tanAtanB)
=(√3 -1)/(1+√3)
now rationalizing it,
(√3 -1)×(√3 -1)/(1+√3)×(√3 -1)
=(√3 -1)²/(3 -1)
=(3+1- 2√3)/2 = 2- √3

Answer 2

Answer:

cosA=0.5,

A=60°

cosB=1\√2,

B=45°

value of tanA-tanB/1+tanA*tanB

√3-1/1+√3*√3-1√3-1=

(√3-1)square/(√3)square-(1)square=

(3+1-2√3)/2=

2-√3