If cos A =2/5 ,find 4+4tan^2A.
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cosA = b/h
so,b= 2
h= 5
p = ✓h^2-b^2
= ✓5^2-2^2
= ✓25-4
= ✓21
then,tanA = p/b = ✓21/2
4+4tan^2A
= 4+4(✓21/2)^2
= 4+4×21/4
= 4+21
= 25
so,b= 2
h= 5
p = ✓h^2-b^2
= ✓5^2-2^2
= ✓25-4
= ✓21
then,tanA = p/b = ✓21/2
4+4tan^2A
= 4+4(✓21/2)^2
= 4+4×21/4
= 4+21
= 25
jazzy3:
as per solve addition
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may it will help u
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