Question

if cos theta = 1/2,find sec2 theta + tan2 theta

Answer 1

solution has been provided to you

Answer 2

Hey !!!

cos¢ = 1/2 = b/h

By using Pythagoras theorem

P = √h² - b²

P = √2² - 1²

P = √4-1 = √3

Now , sec¢ = h/b= 2/1 = 2

Tan¢ = p/b = √3

So, sec²¢ + tan²¢

=] (2)² + (√3)²

=> 4+ 3 = 7

And if question is

sec2¢ + tan2¢ = ?

Than , 2×2 + 2×√3

4+ 2√3

=2(2+√3)

Hope it helps you !!!

#Rajukumar111@@