Question

if cos theta is equal to root 3 by 2 then find the value of 1 minus sec theta divided by 1 + cosec theta​

Answer 1

Answer:

√3 -2 / 6

Step-by-step explanation:

cos Θ = √3/2

sin Θ = 1/2

1 - sec Θ / 1 + cosec Θ

= 1 - 2/√3 / 1 + 2

= √3 - 2 / 2 * 1/3

= √3 - 2 / 6

Answer 2

The value of $\frac{1-sec\theta}{1+cosec\theta}$ = $\frac{3-2\sqrt{3}}{9}$.

• The value of cosθ = √3/2.

• Now using the identity, sin²θ + cos²θ = 1

sin²θ = 1 - (3/4)

sin²θ = 1/4

sinθ = (1/2)

• Now, we have to find the value of $\frac{1-sec\theta}{1+cosec\theta}$.

• Substituting the values in the given expression , we get

$\frac{1-sec\theta}{1+cosec\theta}$ = $\frac{1-(1/cos\theta)}{1+(1/sin\theta)}$

= $\frac{1-2/(\sqrt{3})}{1+(2)}$

= $\frac{(\sqrt{3})-2}{3(\sqrt{3})}$

= $\frac{3-2\sqrt{3}}{9}$