if cos theta + sin theta is equal to root 2 cos theta show that cos theta minus sin theta is equal to root 2 Sin Theta
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let theta = x
cos x + sin x = root2 cos x
squaring on both side, we get......
cos2x + sin2x + 2cosxsinx = 2cos2x
2sinxcosx = 2cos2x - cos2x - sin2x
2sinxcosx = cos2x - sin2x
2sinxcosx = (cosx+sinx) (cosx - sinx)
2sinxcosx = (root2 cosx) (cosx - sinx)
2sinxcosx/root2 cosx = cosx - sinx
root2 sinx = cosx - sinx
paryuljain23:
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Answered by
1
Answer:
Step-by-step explanation:
CosA + sin A = /2cosA
SinA = /2cosA -cos A
= cosA ( /2-1) × (/2+1) ÷ (/2+1)
= cosA÷/2+1
SinA(/2+1)=cos A
To prove = cosA - SinA= /2 sinA
Putting value of cos A
SinA (/2+1)-sinA
/2 sinA + sinA- sinA
=/2sin A
Hence proved
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