if CosA=4/5,CosB=12/13, 3π/2<A<2π and 3π/2<B<2π then the value of cos(A+B) and Sin (A-B)is equal to?
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Step-by-step explanation:
Cos(A+B) = CosA× CosB -SinA× SinB
=(4/5)(12/13) - (3/5)(5/13)
=(48-15)/65
=33/65
Sin(A+B)= SinA× CosB + CosA× SinB
=(3/5)(12/13) + (4/5(5/13)
=(36-20)/65
=16/65
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