Question

if cosA=4/5 then find 4(cot square A - cosec square A)by 3(tan square A - sec square A)​

Answer 1

answer:4/3

cosA=4/5

let base = 4k

hypotenuse=5k

using Pythagoras therom

P²+B²=H²

P²+(4k)²=(5k)²

P²+16k²=25k²

P²=25k²-16k²

P²=9k²

P=3k

cot A=4/3;tanA=3/4;cosecA=5/3;secA=5/4

4(cotA-cosecA)/3(tanA-secA)

4[(4/3)²-(5/3)²]/3[(3/4)²-(5/4)²

4(16/9-25/9)/3(9/16-25/16)

4(-1)/3(-1)

-4/-3

4/3