If cosB=1/3 find the other five trigonometric ratios.
Answers
Answered by
69
Cos B = 1/3 = B/H
B = 1 and H = 3.
By Pythagoras theroem,
( H )² = (B)² + (P)²
( 3)² = (1)² + (P)²
( P )² = 9 - 1
P² = 8
P = √8 = √2 × 2 × 2
P = 2√2.
Therefore,
Sin B = P/H = 2√2/3
Cos B = B/H = 1/3
Tan B = P/B = 2√2/1 = 2√2
Cosec B = H/P = 3/2√2
Sec B = H/B = 3
And,
Cot B = B/P = 1/2√2.
B = 1 and H = 3.
By Pythagoras theroem,
( H )² = (B)² + (P)²
( 3)² = (1)² + (P)²
( P )² = 9 - 1
P² = 8
P = √8 = √2 × 2 × 2
P = 2√2.
Therefore,
Sin B = P/H = 2√2/3
Cos B = B/H = 1/3
Tan B = P/B = 2√2/1 = 2√2
Cosec B = H/P = 3/2√2
Sec B = H/B = 3
And,
Cot B = B/P = 1/2√2.
Answered by
41
Step-by-step explanation:
Cos B = 1/3 = B/H
B = 1 and H = 3.
By Pythagoras theroem,
( H )² = (B)² + (P)²
( 3)² = (1)² + (P)²
( P )² = 9 - 1
P² = 8
P = √8 = √2 × 2 × 2
P = 2√2.
Sin B = P/H = 2√2/3
Cos B = B/H = 1/3
Tan B = P/B = 2√2/1 = 2√2
Cosec B = H/P = 3/2√2
Sec B = H/B = 3
Cot B = B/P = 1/2√2.
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