if cosec A =13/12, then fid the value of 2 sinA -3 cosA /4 sinA-9 cosA
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cosecA=13/12; sinA=12/13(p/h)
So, b² = 13²-12²=> 5=b
Now,
2sinA-3cosA/4sinA-9cosA
= (2x12/13-3x5/13)/(4x12/13-9x5/13)
= (9/13)/(3/13)
= 3.
So, b² = 13²-12²=> 5=b
Now,
2sinA-3cosA/4sinA-9cosA
= (2x12/13-3x5/13)/(4x12/13-9x5/13)
= (9/13)/(3/13)
= 3.
Matrix390:
thnx
whats tan thita - cot thita?
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