If cosec A = root 10 find other five trigonometric ratios
Answers
Answered by
21
If csc A = root(10)/1, construct a triangle that has that csc A as that value.
csc = 1/sin = 1/(opp/hypo) = hypo/opp.
Hence the triangle would have side 1 and hypotenuse root(10). Plugging into the Pythagorean theorem, one can see that the other side is 3. With that out of the way, we can start constructing the other 5 trig ratios. We should also state that we are assuming all angles to be within quadrant 1, otherwise we might be dealing with negatives.
Opposite = 1
Adjacent = 3
Hypotenuse = root(10)
sin = o/h = 1/root(10) = root(10)/10
cos = a/h = 3/root(10) = 3*root(10)/10
tan = o/a = 1/3
sec = root(10)/3
cot = 3/1 = 3
csc = 1/sin = 1/(opp/hypo) = hypo/opp.
Hence the triangle would have side 1 and hypotenuse root(10). Plugging into the Pythagorean theorem, one can see that the other side is 3. With that out of the way, we can start constructing the other 5 trig ratios. We should also state that we are assuming all angles to be within quadrant 1, otherwise we might be dealing with negatives.
Opposite = 1
Adjacent = 3
Hypotenuse = root(10)
sin = o/h = 1/root(10) = root(10)/10
cos = a/h = 3/root(10) = 3*root(10)/10
tan = o/a = 1/3
sec = root(10)/3
cot = 3/1 = 3
Answered by
19
Answer:
Step-by-step explanation:
Attachments:
Similar questions