If cosec theta +cot theta=k, then prove that cos theta =
K²-1÷
k²+1
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Given,
cosece + cot0 = k
cos0
= k
sine
1
sin0
1+cos0
= k
sine
1+ cose =
ksine
Squaring both side,
(1+cos0)² = k²sin²0
(1+ cos0)² = k²(1 – cos?0)
(1+ cos0).(1+cos0) = k²(1+ cos0)(1 –
cos0)
1+ cos0 = k²(1 – cos0)
1+ cos0 = k² – k²cos0
1+(1+k²)cos0 = k?
(1+k²)cos0 = k² – 1
cosθ= k 2 +1k 2−1
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