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Step-by-step explanation:
(1/√2-1) + (2/√3+1) = √2+√3
By Rationalising the denominator,
[1×(√2+1)/(√2-1)(√2+1)] + [2×(√3-1)/(√3-1)(√3+1)] = √2+√3
{In the first part we multiplied and divided with √2+1. In the second part we multiplied and divided with √3-1.}
(√2+1/2-1) + (2√3-2/3-1) = √2+√3
(√2+1/1) + (2√3-2/2) = √2+√3
LCM=2
(2√2+2)/2 + (2√3-2)/2 = √2+√3
(2√2+2+2√3-2)/2 = √2+√3
(2√2+2√3)/2 = √2+√3
2(√2+√3)/2 = √2+√3
√2+√3 = √2+√3
Hence proved//
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