Math, asked by akashdee05011876, 3 months ago

prove step by step ....
as soon as possible​

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Answered by adprasad
1

Step-by-step explanation:

(1/√2-1) + (2/√3+1) = √2+√3

By Rationalising the denominator,

[1×(√2+1)/(√2-1)(√2+1)] + [2×(√3-1)/(√3-1)(√3+1)] = √2+√3

{In the first part we multiplied and divided with √2+1. In the second part we multiplied and divided with √3-1.}

(√2+1/2-1) + (2√3-2/3-1) = √2+√3

(√2+1/1) + (2√3-2/2) = √2+√3

LCM=2

(2√2+2)/2 + (2√3-2)/2 = √2+√3

(2√2+2+2√3-2)/2 = √2+√3

(2√2+2√3)/2 = √2+√3

2(√2+√3)/2 = √2+√3

√2+√3 = √2+√3

Hence proved//

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