if cotB/2=a+c/b find the angle A
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Answer:
A=π/2 .(It took me 14 minutes to type.Pls mark as brainliest)
Step-by-step explanation:
Using the sine law we can rewrite the assumption as
sinA+sinCsinB=cotB2
We can now use the sum-to-product formula and remove the denominator that can be rewritten as 2sin(B/2)cos(B/2) , yielding
2sinA+C2cosA−C2=2cos2B2
Since A+C=π−B , we get
cosB2cosA−C2=cos2B2
and therefore, being cos(B/2)≠0 ,
cosA−C2=cosB2
If A≥C this entails A−C=B , so A=B+C and therefore A=π/2 .
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