Question

x^2+21x+108

this is the question please ans correct if you know​

Answer 1

${x}^{2} + 21x + 108 \\ \\ = {x}^{2} + 12x + 9x + 108 \\ \\ = x(x + 12) + 9x + 108 \\ \\ = x(x + 12) + 9(x + 12) \\ \\ = \green{\boxed{( x + 9)( x + 12)}}...by \: taking \: common \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: factors \: out.$

Answer 2

Answer:

${x}^{2} + 21x + 108 \\ x {}^{2} + 12x + 9x + 108$

$(x + 9)(x + 12)$

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