Question

If csquare is not equal to an and the roots of (csquare-an)xsquare -2(a square-bc)x+(b square-ax)=0 are equal show that a cube+b cube+c cube=3abc(or) a=0

Answer 1

Answer:

a= 0 ￦a-2 its R1 +

$7 \times \frac{8}{5}$