Math, asked by IJAZ10, 1 year ago

if d= HCF(48,72) the value of d is

Answers

Answered by krithikasmart11
1

Answer:

3

Step-by-step explanation:

Given,

d = HCF ( 48, 72 )

To Find,

The value of d.

Concept:

We'll find the Prime Factors of the numbers 48 and 72.

They are as follows:

48 = 2 x 2 x 2 x 2 x 3

72 = 2 x 2 x 2 x 3 x 3

So,

Common Factors = 2 x 2 x 2 x 3

H.C.F = 3

d = 3

Therefore, the answer is 3.

#SPJ3

Answered by DeenaMathew
0

The value of d is 24.

Given:

d= HCF(48,72).

To Find:

The value of d.

Solution:

To find the value of d we will follow the following steps:

As we know,

HCF is the highest common factor between the common factors of two terms.

So, we will first find prime factors for both terms.

The prime factors for 48 = 2 × 2 × 2 × 2 × 3

The prime factors for 72 = 2 × 3 ×2 × 3 × 2

The common factors between 48 and 72 = 2 ×2 ×2 × 3

So, the highest common factor among 2 ×2 ×2 × 3 is 3.

Henceforth, the value of d is 3.

#SPJ3

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